two forces act on an object, force A id 8.7N and force B is 12.9N. The angle between the two forces is 125 degrees. what is the net force on the object?

Fn = 8.7[125o] + 12.9[0o]

X = 8.7*Cos125 + 12.9 = 7.91 N.
Y = 8.7*sin125 = 7.13 N.

Fn = sqrt(X^2+Y^2) = sqrt(7.91^2*7.13^2)
= 10.65 N.

To find the net force acting on an object when two forces are applied at an angle, we need to use vector addition. The net force is the sum of the two forces acting on the object.

To begin, we can break down the forces into their horizontal and vertical components. The horizontal component is found by multiplying the magnitude of the force by the cosine of the angle between the force and the x-axis. The vertical component is found by multiplying the magnitude of the force by the sine of the angle.

For Force A:
Horizontal component of Force A = 8.7 N * cos(125°)
Vertical component of Force A = 8.7 N * sin(125°)

For Force B:
Horizontal component of Force B = 12.9 N * cos(125°)
Vertical component of Force B = 12.9 N * sin(125°)

Next, we can find the horizontal component of the net force by summing the horizontal components of the two forces. Likewise, we can find the vertical component of the net force by summing the vertical components.

Horizontal component of net force = (Horizontal component of Force A) + (Horizontal component of Force B)
Vertical component of net force = (Vertical component of Force A) + (Vertical component of Force B)

Finally, we can find the magnitude of the net force using the Pythagorean theorem:

Magnitude of net force = √((Horizontal component of net force)^2 + (Vertical component of net force)^2)

By performing the calculations, we can find the net force acting on the object.