How would i do a table of values for this equation: y=1/2(3)^-2x starting from -5 to 5

i get these values: -0.2778, -0.2222, -0.1667, -0.1111, -0.0556, 0 etc... am i wrong?

To generate a table of values for the given equation, you need to substitute different values of x into the equation and calculate the corresponding values of y.

Let's start with the equation: y = (1/2) * (3^(-2x))

To create the table, we will substitute values of x ranging from -5 to 5, as you mentioned. Here's how you can calculate the values of y step-by-step:

1. Substitute x = -5 into the equation:
y = (1/2) * (3^(-2 * -5))
y = (1/2) * (3^10)
y ≈ -0.00003892243 (rounded to 10 decimal places)

2. Substitute x = -4 into the equation:
y = (1/2) * (3^(-2 * -4))
y = (1/2) * (3^8)
y ≈ -0.002699796 (rounded to 9 decimal places)

3. Substitute x = -3 into the equation:
y = (1/2) * (3^(-2 * -3))
y = (1/2) * (3^6)
y ≈ -0.1875

4. Continue this process until you reach x = 5.

Here's the table of values:

| x | y |
|-------|-------------|
| -5 | -0.00003892 |
| -4 | -0.00269980 |
| -3 | -0.18750 |
| -2 | -1.31250 |
| -1 | -9.18750 |
| 0 | -64.50000 |
| 1 | -451.50000 |
| 2 | -3154.50000 |
| 3 | -22082.50000|
| 4 | -154577.50000|
| 5 | -1082042.50000|

Please note that the values you provided in your question seem incorrect. Make sure to double-check your calculations or try recomputing the values using the steps provided above.