Math

The sixth term of an A.P. is 5 times the first term and the eleventh term exceeds twice the fifth term by 3 . Find the 8th term ?

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  1. a+5d = 5a
    a+10d = 2(a+4d)+3

    Now you can find a and d, and then a+7d.

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  2. translate the English into Math...
    "The sixth term of an A.P. is 5 times the first term"
    ---> a+ 5d = 5a or 5d = 4a
    a = 5d/4

    "eleventh term exceeds twice the fifth term by 3"
    term(11) -2 term(5) = 3
    a + 10d - 2(a + 4d) = 3
    -a + 2d = 3
    -5d/4 + 2d = 3
    times 4
    -5d + 8d = 12
    d = 4
    then a = (5/4)(4) = 5

    check:
    term6 = a + 5d = 25 which is 5 times the first term
    term 11 = a+10d = 45
    twice term5 = 2(21) = 42 , which is 3 less than term11

    term8 = a + 7d = 5 + 28 = 33

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  3. tikka

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  4. All the best 👍

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  5. answers is write. Thanku
    it is very helpful

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