What is the molarity of a bleach solution containing 6.6 g of NaOCl per liter of bleach?
answer please
Convert 6.6g NaOCl to mols. mols = grams/molar mass.
Then M = mols/L solution
To find the molarity of a solution containing NaOCl, you need to know the moles of NaOCl dissolved per liter of solution.
First, you need to calculate the molar mass of NaOCl:
Mass of Na = 22.99 g/mol
Mass of O = 16.00 g/mol
Mass of Cl = 35.45 g/mol
Molar mass of NaOCl = Mass of Na + Mass of O + Mass of Cl
Molar mass of NaOCl = 22.99 g/mol + 16.00 g/mol + 35.45 g/mol
Now, we can calculate the moles of NaOCl in 6.6 g:
moles of NaOCl = mass of NaOCl / molar mass of NaOCl
moles of NaOCl = 6.6 g / molar mass of NaOCl
Next, we need to find the volume of the bleach solution in liters:
Volume of bleach solution = 1 L
Finally, we can calculate the molarity:
Molarity (M) = moles of NaOCl / Volume of bleach solution
Molarity (M) = moles of NaOCl / Volume of bleach solution = moles of NaOCl / 1 L
So, the molarity of the bleach solution containing 6.6 g of NaOCl per liter of bleach is equal to the calculated moles of NaOCl divided by 1 L.