At what height above the ground must a body of mass 10kg be situated in order to have potential energy in value to the kinetic energy possessed by another body of mass 10kg moving with a velocity of 10m-s

5meter

5m

Ke = (1/2) m v^2 = 500 joules

m g h = 500

10 (9.81) h = 500

To find the height above the ground at which a body of mass 10 kg must be situated to have potential energy equal to the kinetic energy of another body of mass 10 kg moving with a velocity of 10 m/s, we need to equate the two energies.

Potential Energy (PE) is given by the formula: PE = mgh, where m is the mass of the body, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height above the ground.

Kinetic Energy (KE) is given by the formula: KE = (1/2)mv^2, where m is the mass of the body and v is the velocity.

Setting the two energies equal to each other, we have:

mgh = (1/2)mv^2

Since the mass of both bodies is 10 kg, we can cancel out the m:

10gh = (1/2)(10^2)

Simplifying further:

10gh = 50

Dividing both sides by 10:

gh = 5

Now, we can solve for h by dividing both sides by g:

h = 5/g

Using the approximate value of g as 9.8 m/s^2:

h = 5/9.8

Calculating:

h ≈ 0.51 meters

Therefore, the body of mass 10 kg must be situated approximately 0.51 meters above the ground to have potential energy equal to the kinetic energy of another body of mass 10 kg moving with a velocity of 10 m/s.