What is the total pressure of the gas produced in the burette if it contains nitrogen gas whose pressure is 1.5 atm, oxygen gas whose pressure is 1.6 atm and water vapour with a pressure of 1.3 atm.
I don't know where you have it but the sum of the partial pressure of each is the total pressure.
1.5 + 1.6 + 1.3 = ? atm.
You have a tough time getting 1.3 atm H2O vapor unless the container is sealed since the vapor pressure at boiling point is 1 atm.
To find the total pressure of the gas in the burette, you simply need to add up the partial pressures of each gas component.
In this case, the total pressure is the sum of the pressures of nitrogen gas, oxygen gas, and water vapor. Given that the pressure of nitrogen gas is 1.5 atm, oxygen gas is 1.6 atm, and water vapor is 1.3 atm, you can calculate the total pressure as follows:
Total pressure = Pressure of nitrogen gas + Pressure of oxygen gas + Pressure of water vapor
Total pressure = 1.5 atm + 1.6 atm + 1.3 atm
Total pressure = 4.4 atm
Therefore, the total pressure of the gas produced in the burette is 4.4 atm.