The width and area of a rectangle are shown in the figure at the right. What is the length of the rectangle?

(the rectangle:)

A = (4b^3 + 5b - 3) in.^2
Width = (2b - 1) in.

Pls help!? Thx

well, consider that

4b^3+5b-3 = (2b-1)(2b^2+b+3)

To find the length of the rectangle, we need to use the given information about the width and area of the rectangle.

From the given information, we can determine that the width of the rectangle is (2b - 1) inches.

The formula for the area of a rectangle is length multiplied by width. So, we can set up an equation using the area formula:

A = length * width

Substituting the given values into the equation:

(4b^3 + 5b - 3) = length * (2b - 1)

To solve for the length, we need to isolate it on one side of the equation. To do this, we can divide both sides of the equation by (2b - 1):

(4b^3 + 5b - 3) / (2b - 1) = length

This gives us the length of the rectangle in terms of 'b'.