# geomtry

A diameter of a circle has endpoints P(-10,2) and Q(4,6)
a. find the center of the circle.
c. write an equation for the circle

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1. The center is the midpoint of PQ: (-3,4)
The radius is half the length of PQ: 1/2 √(14^2+4^2)

Now, knowing the center and the radius, you know that the equation is

(x+3)^2 + (y-4)^2 = r^2

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2. 👎
2. i got (x+3)^2 + (y-2)^2=65

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2. 👎

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