Three charged particles are arranged on corners of a square as shown in the figure below, with charge -Q on both the particle at the upper left corner and the particle on the lower right corner, and charge +2Q on the particle at the lower left corner.

(i) What is the direction of the electric field at the upper right corner, which is a point in empty space?
a. It is upward and to the right.
b. It is straight to the right.
c. It is straight downward.
d. It is downward and to the left.
e. It is perpendicular to the plane of the picture and outward.
f. There is no direction; no field exists at that corner because no charge is there.
g. There is no direction; the total field there is zero

(ii) Suppose the +2Q charge at the lower left corner is removed. Then does the magnitude of the field at the upper right corner
a. become larger
b. become smaller
c. stay the same
d. change unpredictably

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To determine the direction of the electric field at the upper right corner, we need to consider the individual electric fields created by each charged particle and then find the net electric field.

(i) To find the direction of the electric field at the upper right corner:
- The electric field created by the -Q charge at the upper left corner will point away from it.
- The electric field created by the +2Q charge at the lower left corner will point towards it.
- The electric field created by the -Q charge at the lower right corner will also point towards it.

Considering these individual electric fields, we can see that the electric field vectors created by the lower left and lower right charges will cancel each other out, leaving only the electric field created by the upper left charge.

So, the direction of the electric field at the upper right corner is upward and to the right.

Therefore, the correct answer is (a) It is upward and to the right.

(ii) If the +2Q charge at the lower left corner is removed, the magnitude of the field at the upper right corner will change.

Without the +2Q charge, the electric field created by that charge will no longer contribute to the net electric field at the upper right corner. As a result, the magnitude of the field will become smaller.

Therefore, the correct answer is (b) become smaller.

Answer is C

a up to the right and it gets smaller if take out +2 charged particle

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