how do you find additional points on a line with a slope of 1/2 and a given point of (7,-2)?
im sorry but i still cant get an answer
for this question.
this is pretty simple
you just find the equation of the line, this would be
y=1/2(x+2)+7
=1/2x + 8
and if you graph that, u should be able to pick any addional points on that line.
To find additional points on a line with a given slope and a given point, you can follow these steps:
1. Begin with the given point (7, -2).
2. Use the given slope of 1/2, which represents "rise over run." This means that for every 1 unit of rise (vertical), there will be 2 units of run (horizontal).
3. Move 1 unit up and 2 units right from the given point. This represents the "rise" and "run" values based on the slope. So, starting from (7, -2), add 1 to the y-coordinate and 2 to the x-coordinate, resulting in the point (7 + 2, -2 + 1) = (9, -1).
4. This new point (9, -1) lies on the line with the given slope of 1/2.
5. You can repeat steps 3 and 4 as many times as needed to find additional points on the line. Each time, move 1 unit up and 2 units right from the previous point.
Therefore, the additional points on the line with a slope of 1/2 and a given point of (7, -2) are (9, -1), (11, 0), (13, 1), and so on.