1. How many 2-digit numbers can be formed using only the digits 2, 3, 5, and 6, if the digits are not to be repeated within a number?
11
12**
10
2
2. How many different ways are there to rearrange the letters of the word EXAM if you don't care if the result is a recognizable word?
4
12
24**
256
Please help thanks! @Ms. Sue, @Reed, @Writeacher
this was all the way back in 2015 and nobody has given caleidoscope the answers he/she/they seek besides steve. and even then nobody is backing steve up. when im done with the test i will verify these answers.
both are correct.
Both answers are correct. i doubt caleidoscope will see this tho since this was seventh grade math at the end of the school year, meaning caleidoscope is in highschool if they were kept back a grade or they have graduated by now.
1. To find the number of 2-digit numbers that can be formed using the digits 2, 3, 5, and 6 without repeating digits, we can use a combination of counting principles.
First, we need to determine the number of choices for the tens digit. Since it cannot be zero, we have four options: 2, 3, 5, and 6.
Next, we find the number of choices for the units digit. Since it should not be the same as the tens digit, we have three remaining options.
To get the total number of 2-digit numbers, we multiply the number of choices for the tens digit (4) by the number of choices for the units digit (3):
Number of 2-digit numbers = 4 * 3 = 12
Therefore, the correct answer is 12.
2. To find the number of different ways to rearrange the letters of the word EXAM, we need to determine the number of distinct arrangements when all letters are considered as unique.
The word EXAM has four distinct letters: E, X, A, and M. Each letter can be placed in any of the four positions.
To calculate the total number of arrangements, we multiply the number of choices for the first position (4) by the number of choices for the second position (3), then multiply the result by the number of choices for the third position (2), and finally multiply by the number of choices for the fourth position (1):
Total number of arrangements = 4 * 3 * 2 * 1 = 24
Therefore, the correct answer is 24.