The density of 2 molal aqueous solution of NaOH is 1.10gm/L. Calculate the molarity of the solution.
2 m is 2 mols/kg solvent
2 mols NaOH = 2*40 = 80 g NaOH
Total mass solution is 1000 + 80 = 1080 g.
mass = volume x density. You know the density and mass, solve for volume, then M = mols/L
Can u solvee full anss
To find the molarity of the solution, we can use the formula:
\(\text{Molarity} = \frac{\text{moles of solute}}{\text{volume of solution in liters}}\)
Given that the density of the solution is 1.10 g/mL and we have a 2 molal solution, we can first convert the density to grams per liter. Since 1 mL = 1 g, the density of the solution is equal to its concentration in g/L.
Now let's find the mass of the solute (NaOH) in 1 L of the solution:
\(\text{Mass of solute in 1 L} = \text{density} \times \text{volume}\)
\(\text{Mass of solute in 1 L} = 1.10 \, \text{g/L} \times 1 \, \text{L} = 1.10 \, \text{g}\)
The molarity of the solution is defined in terms of moles of solute per liter of solution. Since the solution has 2 molal NaOH, this means there are 2 moles of NaOH in every 1 kg (1000 g) of water.
Thus, the number of moles of NaOH in 1.10 g is calculated as:
\(\text{Number of moles of NaOH} = \frac{\text{mass of solute}}{\text{molar mass of NaOH}}\)
\(\text{Number of moles of NaOH} = \frac{1.10 \, \text{g}}{40.00 \, \text{g/mol}} = 0.0275 \, \text{mol}\)
Finally, we can calculate the molarity of the solution:
\(\text{Molarity} = \frac{\text{moles of solute}}{\text{volume of solution in liters}}\)
\(\text{Molarity} = \frac{0.0275 \, \text{mol}}{1 \, \text{L}} = 0.0275 \, \text{M}\)
Therefore, the molarity of the 2 molal aqueous solution of NaOH is 0.0275 M.
To calculate the molarity of a solution, we need to know the number of moles of solute (NaOH) and the volume of the solution.
In this case, we are given the density of the solution and we need to first calculate the mass of NaOH in the solution.
Density is defined as mass/volume. Rearranging the equation, we have:
mass = density * volume
The density of the 2 molal NaOH solution is given as 1.10 gm/L. Let's say the volume of the solution is V liters.
So, the mass of NaOH in the solution can be calculated as:
mass of NaOH = density * volume = 1.10 gm/L * V L
Now, we need to convert the mass of NaOH to moles. To do this, we need to know the molar mass of NaOH.
The molar mass of NaOH can be calculated by adding up the atomic masses of sodium (Na), oxygen (O), and hydrogen (H) in one molecule of NaOH.
Na = 22.99 g/mol
O = 16.00 g/mol
H = 1.01 g/mol
Molar mass of NaOH = Na + O + H = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol
Now, we can calculate the number of moles of NaOH in the solution using the mass and molar mass:
moles of NaOH = mass of NaOH / molar mass of NaOH
Finally, we can calculate the molarity of the solution using the number of moles of NaOH and the volume of the solution:
molarity = moles of NaOH / volume of solution (in liters)
So, by plugging in the values, we can calculate the molarity of the solution.