A bag held 3 red marbles, 1 blue marble, and 4 yellow marbles. Lee drew a red marble and did not replace it. What is the probability of drawing a yellow marble next?
A. 1/4
B. 1/3
C. 1/2
D. 4/7
4/(8-1) = ?
4/7
To determine the probability of drawing a yellow marble next, we need to consider the total number of marbles remaining in the bag and the number of yellow marbles remaining.
Initially, the bag contains a total of 3 red marbles + 1 blue marble + 4 yellow marbles = 8 marbles.
After Lee draws a red marble and does not replace it, there are now a total of 7 marbles remaining in the bag: 2 red marbles + 1 blue marble + 4 yellow marbles = 7 marbles.
Out of the 7 remaining marbles, there are still 4 yellow marbles.
Therefore, the probability of drawing a yellow marble next can be calculated as the number of favorable outcomes (drawing a yellow marble) divided by the number of total possible outcomes.
Probability = Number of favorable outcomes / Number of total possible outcomes
In this case, the number of favorable outcomes is 4 (remaining yellow marbles), and the number of total possible outcomes is 7 (remaining marbles).
Probability = 4/7
So the probability of drawing a yellow marble next is 4/7.
Therefore, the correct option is D. 4/7.