(x^2 + 6x + 9 over x - 1 over x^2 - 9 over x^2 - 2x +1.
So it's a fraction over a fraction.
use / to show division
(x^2 + 6x + 9 )/(x-1) ÷ ((x+3)(x-3))/(x-1)^2
= (x+3)^2 /(x-1) * (x-1)^2/((x-3)(x+3))
= (x+3)(x-1)/(x-3) , x ≠ 1, ± 3
So it's a fraction over a fraction.
(x^2 + 6x + 9 )/(x-1) ÷ ((x+3)(x-3))/(x-1)^2
= (x+3)^2 /(x-1) * (x-1)^2/((x-3)(x+3))
= (x+3)(x-1)/(x-3) , x ≠ 1, ± 3