What do I do with this??
3^3/3^6
A.1/27
B.1/9
C.9
D.-27
What do I do to solve this?? Thanks
3^3/3^6
=
3*3*3
-----------------
3*3*3*3*3*3
Now you can see that three 3's cancel out in top and bottom, so you are left with
1/(3*3*3) = 1/27
This shows why x^n / x^m = x^(n-m)