ok so I have no idea what I'm suppose to do or what this question is even asking me...
determine the units of the quanity described by the following combinations of units:
a. kg (m/s)(l/s)
b. (kg/s)(m/s^2)
c. (kg/s) (m/s)^2
d. (kg/s) (m/s)
a. kg (m/s)(l/s)
this is kg m/s^2
which is mass times acceleration
which is force in Newtons
b. this is Newtons/second, beats me
c. kg m/s^2 * m/s
this is force in Newtons times distance/second
which is work per second
which is power in watts
d. looks the same as a to me
In each case, you can just multiply the units together to get the "units" of the answer. You can also rewrite kg m/s^2 as Newtons or kg (m/s)^2 as Joules
1. Is the "l" supposed to be liters? or the number 1?
If liters, then the combination is Newton-liters, or 10^-3 Joule*m^2
2. N/s
3. J/s
4. N
No problem! Let's break down the question step by step.
To determine the units of a given quantity, we need to understand the units involved in the combination of terms. Units are used to express measurements or quantities in terms of a standard reference.
a. kg (m/s)(l/s):
To find the units for this combination, we multiply the individual units together:
kg (m/s)(l/s) = kg m/s * l/s
So, the units for this combination are kg m/s * l/s.
b. (kg/s)(m/s^2):
Similarly, we multiply the individual units:
(kg/s)(m/s^2) = kg m/(s^3)
Therefore, the units for this combination are kg m/(s^3).
c. (kg/s) (m/s)^2:
Again, we multiply the individual units:
(kg/s) (m/s)^2 = kg m^2/(s^3)
Hence, the units for this combination are kg m^2/(s^3).
d. (kg/s) (m/s):
Once more, we multiply the individual units:
(kg/s) (m/s) = kg m/(s^2)
Thus, the units for this combination are kg m/(s^2).
Remember, when determining units, it's important to keep track of the operations (multiplication, division, exponentiation) and their corresponding units.