if the actual mass of oxide at the end of the experiment is 130g, what is percentage yield?

if the actual mass of iron oxide is 130g , what is the percentage yield ?

so how can we try it because 2mrw is wanted?

To calculate the percentage yield, you need to compare the actual yield to the theoretical yield. The percentage yield is given by the formula:

Percentage Yield = (Actual Yield / Theoretical Yield) × 100

In this case, the actual mass of the oxide at the end of the experiment is given as 130g. However, we do not have the information to calculate the theoretical yield. The theoretical yield is the maximum amount of product that could be obtained under ideal conditions. It depends on the balanced chemical equation and the stoichiometry of the reaction.

To calculate the theoretical yield, you would need the balanced chemical equation, the molar masses of the reactants and products, and the reactant stoichiometry (the coefficients in the balanced equation). With these values, you can calculate the moles of reactant and product involved in the reaction, and then convert those to grams using their molar masses.

Once you have the actual and theoretical yields, you can use the formula mentioned earlier to calculate the percentage yield. However, without the information required for calculating the theoretical yield, we cannot determine the percentage yield in this case.

Percent Yield = (Actual Yield / Theoretical Yield) x 100

I think your data is insufficient, since we don't know how much is the theoretical yield.