What is “a, b and c” in this hyperbola?
(y-2)^2/5-(x-3)^2/6=1
Well, the standard form is
(y-k)^2/b^2 - (x-h)^2/a^2 = 1
and for an hyperbola, c^2 = a^2+b^2
(y-2)^2/5-(x-3)^2/6=1
(y-k)^2/b^2 - (x-h)^2/a^2 = 1
and for an hyperbola, c^2 = a^2+b^2