HI. THE REGION INCLUDING THE CIRCLE AT THE FREE-THROW LINE TO THE BASELINE IS GIVEN. FIND THE AREA OF THE REGION. USE PI AS 3.14. IN THE PICTURE GIVEN, ITS 12 FEET BY 19 FEET RECTANGLE WITH A CIRCLE INTERSECTION AS A FREE-THROWN LINE.
you have 1/2 of a circle of radius 12
and a rectangle that is 12x19
You just add up those areas.
Am I on the right track? 12 x 19 = 228 then Area = pi x r x 2 which would be A= 3.14 (6) (6), Therefore Area = 113.04. The final answer would be 228 + 113.04 = 341.04
To find the area of the region between the circle and the rectangle, we need to calculate the areas of both shapes separately and then subtract the area of the circle from the area of the rectangle.
Let's calculate the area of the rectangle first:
Given that the rectangle is 12 feet by 19 feet, we can use the formula for the area of a rectangle, which is length times width:
Area of rectangle = length * width
Area of rectangle = 12 feet * 19 feet = 228 square feet
Now, let's calculate the area of the circle:
The formula for the area of a circle is pi times the radius squared. However, the radius is not given directly, but we can calculate it using the diameter of the circle. The diameter is the same as the width of the rectangle, which is 12 feet. Therefore, the radius is half of the diameter, so the radius is 12 feet / 2 = 6 feet.
Area of circle = pi * radius^2
Area of circle = 3.14 * (6 feet)^2
Area of circle = 3.14 * 36 square feet = 113.04 square feet (rounded to two decimal places)
Now, to find the area of the region between the circle and the rectangle, we subtract the area of the circle from the area of the rectangle:
Area of region = Area of rectangle - Area of circle
Area of region = 228 square feet - 113.04 square feet
Area of region = 114.96 square feet (rounded to two decimal places)
Therefore, the area of the region between the circle and the rectangle is approximately 114.96 square feet.