The perimeter of a rectangle is 68 f. Find the dimensions of the rectangle if the ratioof the length to the width is 9:8

I am sorry that nobody has responded earlier.

The perimeter is the sum of the length of the four sides. Therefore:

2(9X) + 2(8X) = 68

Solve for X. Then 9X and 8X will give you the dimensions.

I hope this helps. Thanks for asking.

To find the dimensions of the rectangle, we can first set up an equation using the given information.

Let's assume the length of the rectangle is 9X and the width is 8X, where X is a variable.

The formula for the perimeter of a rectangle is P = 2L + 2W, where L is the length and W is the width.

So, the equation can be written as:

2(9X) + 2(8X) = 68

Now, we can simplify the equation:

18X + 16X = 68

Combining like terms, we get:

34X = 68

To solve for X, we can divide both sides of the equation by 34:

X = 68/34

X = 2

Now that we have the value of X, we can substitute it back into the expressions for the length and width:

Length = 9X = 9 * 2 = 18

Width = 8X = 8 * 2 = 16

Therefore, the dimensions of the rectangle are 18 feet for the length and 16 feet for the width.