the density of a certain aqueous solution is 1.17g/ml, and the solution is 3.57% by mass NaOH. how many ml of this solution would you need to use in order to prepare 100.0 ml of .150 M NaOH solution?
I'm not sure where to start and what the process to go through would be... Help!
The density of the solution is 1.17 g/mL. How much does a liter weigh?
1.17 g/mL x 1000 mL = ?? grams = mass of soln.
How much of that is NaOH? 0.0357%; therefore, ?? g soln x 0.0357 = ??g NaOH.(The remainder is the mass of the water in the solution).
How many mols NaOH is that? ??gNaOH/molar mass NaOH.
So that many mols in a liter of solution is the molarity.
Then M x mL = M x mL OR
M x mL = 0.150 x 100 mL.
You know M from above and that leaves only mL. Solve for that.
Check my thinking. Check my work. Post your work if you get stuck.
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To solve this problem, you need to calculate the mass of NaOH in the 100.0 ml of 0.150 M NaOH solution. Then, using the density of the given solution, you can determine the volume of the solution needed.
Here's the step-by-step process to find the volume of the solution:
Step 1: Calculate the molar mass of NaOH
The molar mass of NaOH is found by adding the atomic masses of sodium (Na), oxygen (O), and hydrogen (H). The atomic masses are:
Na: 22.99 g/mol
O: 16.00 g/mol
H: 1.01 g/mol
So,
Molar mass of NaOH = (22.99 g/mol) + (16.00 g/mol) + (1.01 g/mol) = 40.00 g/mol
Step 2: Calculate the mass of NaOH needed in 100.0 ml of 0.150 M NaOH solution
To find the mass of NaOH, we need to use the molar mass and the molarity of the solution:
Molarity (M) = moles of solute / liters of solution
Therefore, moles of solute = Molarity × liters of solution
In this case, the molarity is 0.150 M and the volume is 100.0 ml (0.1000 L), so:
moles of NaOH = (0.150 mol/L) × (0.1000 L) = 0.015 mol NaOH
Now, use the molar mass of NaOH to calculate the mass:
mass of NaOH = moles of NaOH × molar mass of NaOH
mass of NaOH = (0.015 mol) × (40.00 g/mol) = 0.600 g NaOH
Step 3: Calculate the volume of the solution needed
We are given that the density of the solution is 1.17 g/ml. Now we can use this information to determine the volume of the solution needed:
density = mass / volume
volume = mass / density
volume = 0.600 g / 1.17 g/ml = 0.513 ml
Therefore, you would need to use approximately 0.513 ml of the given solution to prepare 100.0 ml of 0.150 M NaOH solution.
Note: When carrying out calculations, it's important to use the correct number of significant figures and units to ensure accurate results.