Algebra

Solve for y in terms of x . Determine if y is a function of x . If it is, rewrite using notation and determine the domain.


xsquared+12x-3y+9=0

is it
xsquared + 12x +9=3y
f(x)=xsquared + 12x + 6=y ?

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asked by Nicole
  1. no, should be

    y = (1/3)x^2 + 4x + 3
    (each term had to be divided by 3)

    and yes, it is a function whose domain is the set of real numbers

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    posted by Reiny
  2. y=x^2+12x+6

    Now, is y a function of x?

    What is the domain of x?

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    posted by bobpursley
  3. please disregard

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    posted by bobpursley
  4. Y=5+-6
    y=7+-6X=2
    7+=-6=4
    y=8-6=8+4=12

    SO THE APPLICATION OF X IS ABOUT TO MOVE EXACTLY WERE IT IS AND NEGATIVELY MOVE TO THE POSITIVE NUMBER SO THE ANSWER IS

    NEGATIVE 12

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    posted by Anonymous

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