can someone show me how to do this one i have plenty of them so can you show me step by step when someone gets a chance. Thank you.
Solve the system by graphing
x+y=3
x+y=-1
What I would do is to put the equations in slope intercept form:
y= -x + 3
y= -x -1
Then graph the lines, and see if they cross. If they intersect, that is the solution.
In this case, both lines have the same slope, and are parallel, and never intersect. There is no solution.
Thank you for your help .....
To solve the system of equations x + y = 3 and x + y = -1 by graphing, you can follow these steps:
Step 1: Rewrite the equations in slope-intercept form.
Rewrite x + y = 3 as y = -x + 3.
Rewrite x + y = -1 as y = -x - 1.
Step 2: Plot the lines on a graph.
To graph the first equation y = -x + 3, you can start by plotting the y-intercept, which is (0, 3). Then, you can use the slope, which is -1, to find another point. For example, if you move one unit to the right (x + 1) and one unit down (-1), you will get (1, 2). Connect these two points to draw the line.
To graph the second equation y = -x - 1, follow the same process. Start by plotting the y-intercept, which is (0, -1), and then use the slope, which is also -1, to find another point. For example, if you move one unit to the right (x + 1) and one unit down (-1), you will get (1, -2). Connect these two points to draw the line.
Step 3: Determine if the lines intersect.
After graphing both lines, observe if they intersect. If the lines intersect at a point, that point represents the solution to the system of equations. However, if the lines are parallel and never cross, as in this case, there is no solution to the system.
In the example you provided, the lines are parallel and do not intersect. Therefore, there is no solution to the system of equations x + y = 3 and x + y = -1.
I hope this explanation helps! Let me know if you have any further questions.