each individual letter of the word Tallahassee is placed on a piece of paper and all 11 pieces of paper are placed in a hat. If one letter is selected at random from the hat, determine the probability that the letter T or E is selected.
In the word "Tallahassee", there is only one letter T out of 11 letters, so the probability of getting a T is 1/11.
There are 2 letter E in the word, so probability of getting an E is 2/11.
The probability of getting a letter T OR letter E is therefore
1/11 + 2/11 = 3/11
hope this helps~ `u`
4x-5y-4z=2. X+8y+4z=8. 16x-20y-16z=8 solve the following system
To determine the probability of selecting the letter T or E from the hat, we need to find the total number of favorable outcomes (letters T or E) and the total number of possible outcomes (all 11 letters in the word Tallahassee).
The word Tallahassee consists of 11 letters, so there are 11 pieces of paper in the hat.
Step 1: Find the total number of favorable outcomes (letters T or E):
The word Tallahassee has only two occurrences of the letter T and only two occurrences of the letter E. So, there are a total of 2 + 2 = 4 favorable outcomes.
Step 2: Find the total number of possible outcomes (all 11 letters):
Since there are 11 letters in the word Tallahassee, there are a total of 11 possible outcomes.
Step 3: Calculate the probability:
Probability = (Number of favorable outcomes) / (Number of possible outcomes)
Probability = 4 / 11
Therefore, the probability of selecting the letter T or E from the hat is 4/11.