a hockey player makes a slap shot, exerting a constant force of 25.0N on the puck for .16 seconds. What is the magnitude of the impulse given to the puck

To find the magnitude of the impulse given to the puck, you can use the impulse-momentum principle which states that impulse is equal to the change in momentum of an object.

Impulse = Change in momentum

The formula for impulse is given by:

Impulse = Force × Time

In this case, the force exerted by the hockey player is 25.0 N and the time for which the force is applied is 0.16 seconds.

Plug these values into the formula:

Impulse = 25.0 N × 0.16 s

Calculating the impulse gives:

Impulse = 4.0 kg⋅m/s

Therefore, the magnitude of the impulse given to the puck is 4.0 kg⋅m/s.

To find the magnitude of the impulse given to the puck, you can use the equation:

Impulse = Force × Time

Given that the hockey player exerts a constant force of 25.0N on the puck for 0.16 seconds, you can substitute these values into the equation to find the impulse:

Impulse = 25.0N × 0.16s

Now, let's calculate the impulse:

Impulse = 4.0 N·s

So, the magnitude of the impulse given to the puck is 4.0 N·s.

Impulse = F*t = 25 * 0.16 = 4

A hockey player make the slapshot exerting a concept force of 40.0N on the puck for 0.20 seconds. What is the magnitude for the impulse given to the puck?