Please help me

find the slope of a line that is perpindicular to the line to the line containing the points -2, -1 and 2, -3.

m = -2
m = 2
m= -1/2
m = -1

I think it is a, but I have no idea

first, find the slope of the line, then take the negative reciprocal.

slopw of line; m=&y1-y2)/(x1-x2)=(-1--3)/(-2-2)=2/-4= -1/2

what is the negative of the reciprocal of that?

-2/1?

Nope, take the reciprocal of -1/2, then multiply it by -1

of course.

so it is m = 2?

To find the slope of a line that is perpendicular to another line, you need to first find the slope of the original line.

Given two points (-2, -1) and (2, -3), you can find the slope of the line passing through these points using the slope formula:

m = (y2 - y1) / (x2 - x1)

Substituting the coordinates, we get:

m = (-3 - (-1)) / (2 - (-2))
m = (-3 + 1) / (2 + 2)
m = -2 / 4
m = -1/2

So the slope of the original line is -1/2.

Now, to find the slope of the perpendicular line, you need to take the negative reciprocal of the original slope.

The negative reciprocal of -1/2 is 2. Therefore, the slope of the line perpendicular to the original line is 2.

So, the correct answer is b) m = 2.