A private plane traveled from Seattle to a rugged wilderness , at an average speed of 252 mph . on the return trip , the average speed was 180 mph . if the total time was 9 hours how far is Seattle from the wildness
To find the distance between Seattle and the wilderness, we can use the formula:
Distance = Speed × Time
Let's break down the problem into two parts, the outbound and return trips.
Let's assume the distance between Seattle and the wilderness is D miles.
Outbound trip:
The average speed is given as 252 mph. Let's say it took t1 hours for the outbound trip.
So, we have the equation: D = 252 × t1
Return trip:
The average speed on the return trip is 180 mph. Since the total time is 9 hours and we know the outbound trip took t1 hours, the return trip took 9 - t1 hours.
So, we have the equation: D = 180 × (9 - t1)
Now we can equate the two equations to solve for D:
252 × t1 = 180 × (9 - t1)
Simplifying the equation:
252t1 = 1620 - 180t1
432t1 = 1620
t1 = 1620 / 432
t1 = 3.75 hours
Now, we can substitute this value back into any of the equations to find the distance. Let's use the first equation from the outbound trip:
D = 252 × t1
D = 252 × 3.75
D = 945 miles
So, Seattle is approximately 945 miles away from the wilderness.
distance=speed*time
d=252*tgoing
d=180*(9-tgoing)
set them equal, solve for time going, then solve for distance.