40 LITRES OF A MIXTURE OF MILK AND WATER CONTAINS 10% OF WATER, THE WATER TO BE ADDED, TO MAKE THE WATER CONTENT 20% IN THE NEW MIXTURE IS?

.10(40) + 1.00(x) = .20(40+x)

To solve this problem, we need to determine the amount of water that needs to be added to the mixture to achieve a 20% water content.

Let's break down the given information:
- The initial mixture contains 10% water.
- The total volume of the mixture is 40 liters.

We can start by finding the amount of water in the initial mixture:
Water content = 10% (0.10) * 40 liters = 4 liters

Next, we need to determine the target water content of the new mixture, which is 20%.
Since the total volume of the new mixture is still 40 liters, let's assume that x liters of water need to be added.

Now, we can set up an equation to solve for x:
(4 liters + x liters) / 40 liters = 20% (0.20)

To solve for x, we can multiply both sides of the equation by 40 liters:
4 liters + x liters = 0.20 * 40 liters
4 liters + x liters = 8 liters

Now, let's isolate x by subtracting 4 liters from both sides of the equation:
x liters = 8 liters - 4 liters
x liters = 4 liters

Therefore, 4 liters of water need to be added to the mixture to achieve a 20% water content in the new mixture.