physics

A ball is thrown straight upward from ground level with a velocity of 41 m/s How much time passes before the ball strikes the ground? Disregard air resistance.

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  1. Use the formula:
    h = vo*t - (1/2)gt^2
    We know that
    vo = 41
    g = 9.8
    h = 0 (since it strikes the ground)

    0 = 41t - (1/2)(9.8)t^2

    Solve for t. One of the answers is t = 0, but this is the time before the release of the ball. Get the other value of t.

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