10.0 g of H2SO4 are added to 50. 0 mL of water.
Is the answer 200. If not how do you approach the problem to get the solution.
The answer to what question is 200?
•If the question is to find the % by mass, then
(50.0mL)(1.00g/mL) = 50.0g H2O, and
mass% = (100)[10.0g / (10.0g + 50.0g)] = 16.67%
•If the question is to find the grams/liter, then
[(10.0g)/(50.0mL)](1000mL/L) = 200 g/L
•If the question is to find the # of moles / L, then divide the previous answer by the molar mass of H2SO4.