what is the chemical formula for the reaction between lead acetate and potassium iodide?
please show both reactants and products. :)
You need to know solubility rules and reasons why reactions take place.
Pb(C2H3O2)2(aq) + 2KI(aq) ==> PbI2(s) + 2KC2H3O2(aq)
http://www.chem.vt.edu/RVGS/ACT/notes/solubility_rules.html
The reaction between lead(II) acetate (Pb(C2H3O2)2) and potassium iodide (KI) can be represented by the following chemical equation:
Pb(C2H3O2)2 + 2KI → PbI2 + 2KC2H3O2
In this equation, lead(II) acetate and potassium iodide react to form lead(II) iodide and potassium acetate as the products.
To determine the chemical formula for the reaction between lead acetate and potassium iodide, we need to first understand the chemical formulas of each reactant separately.
Lead acetate has the chemical formula Pb(C2H3O2)2. This means it consists of one lead atom (Pb), two carbon atoms (C), four hydrogen atoms (H), and four oxygen atoms (O) arranged in the compound.
Potassium iodide has the chemical formula KI. It consists of one potassium atom (K) and one iodine atom (I) bonded together.
Now that we know the chemical formulas of the reactants, we can predict the products of the reaction by combining the reactants and balancing the charges.
The reaction between lead acetate and potassium iodide can be represented as follows:
Pb(C2H3O2)2 + 2KI → PbI2 + 2CH3COOK
In this reaction, the lead acetate (Pb(C2H3O2)2) reacts with the potassium iodide (KI) to form lead(II) iodide (PbI2) and potassium acetate (CH3COOK). The balanced equation indicates that one molecule of lead acetate reacts with two molecules of potassium iodide to produce one molecule of lead(II) iodide and two molecules of potassium acetate.
By understanding the chemical formulas of reactants and predicting the products based on their charges and bonding, we can determine the chemical formula for the reaction between lead acetate and potassium iodide.