If the volume is 226 L at 1.7 atm, find the
volume at 2.8 atm. Assume the temperature
and amount of gas remain constant.
Answer in units of L.
226 / 1.7 = 132.94
132.94 x 2.8 = ?
Are there any answer choices? It'd be helpful if there was any
I don't believe the answer by anonymous will get it. Use P1V1 = P2V2
226 x 1.7 = 2.7V2.
Solve for V2.
To find the volume at 2.8 atm, given the initial volume at 1.7 atm, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when the temperature and amount of gas remain constant.
Boyle's Law can be expressed using the formula:
P₁ * V₁ = P₂ * V₂
Where:
P₁ = initial pressure (1.7 atm)
V₁ = initial volume (226 L)
P₂ = final pressure (2.8 atm)
V₂ = final volume (to be determined)
Now, let's solve for V₂:
P₁ * V₁ = P₂ * V₂
Substituting the given values:
(1.7 atm) * (226 L) = (2.8 atm) * V₂
To isolate V₂, divide both sides of the equation by 2.8 atm:
V₂ = (1.7 atm * 226 L) / 2.8 atm
Calculating this expression:
V₂ = 437.857 L
Therefore, the volume at 2.8 atm, assuming the temperature and amount of gas remain constant, is approximately 437.857 L.