Bromine is a red liquid at 25°C. Its density is 3.12 g/mL. What is the volume of 28.1 g of liquid bromine?
mass = volume x density
You know d and m, substitute and solve for v.
To find the volume of 28.1 g of liquid bromine, we can use the density formula:
Density = Mass / Volume
We know that the density of bromine is 3.12 g/mL. Let's assume the volume of bromine is V mL.
Substituting the given values into the formula, we have:
3.12 g/mL = 28.1 g / V mL
Now we can solve for V by rearranging the formula:
V mL = 28.1 g / 3.12 g/mL
V mL = 9.006 mL
Therefore, the volume of 28.1 g of liquid bromine is approximately 9.006 mL.
To find the volume of 28.1 g of liquid bromine, we can use the formula:
Volume = Mass ÷ Density
Given that the mass of the bromine is 28.1 g and the density is 3.12 g/mL, we can substitute these values into the formula:
Volume = 28.1 g ÷ 3.12 g/mL
Now, let's calculate the volume:
Volume = 9.01 mL
Therefore, the volume of 28.1 g of liquid bromine is 9.01 mL.