Integral of (1/root over 1-x^2)(1/inverse of sin xdx) .what is the value?

1 answer

let u = arcsin(x)

then
du = 1/sqrt(1-x^2) dx

now your integrand is just

1/u du

Think you can handle that one?

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Integral of (1/root over 1-x^2)*(1/inverse of sin x*dx) .what is the value?

let u = arcsin(x)

Integral of (1/root over 1-x^2)(1/inverse of sin xdx) .what is the value?