chemistry

Given a percent yield of 45.0% for the reaction:
H2 + Cl2 → 2 HCl(g)
How many moles of HCl gas are produced
if 15.5 L of Cl2 at STP and excess H2 are
reacted?
1. 0.769 mol
2. 0.346 mol
3. 0.622 mol
4. 3.08 mol
5. 1.38 mol
6. 0.156 mol

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  3. 👁 1,436
  1. With gases you may use a shortcut in which L are used directly as mols.

    L H2 @ STP and 100% yield = 15.5L Cl2 x (2 mols HCl/1 mol Cl2) = 31 L H2O at 100%. At 45% it is 31 x 0.45 = ? L HCl

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    2. 👎 2
  2. 0.98

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  3. b nh

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    2. 👎 2
  4. 0.622 mol

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    2. 👎 0

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