Questions LLC
Login
or
Sign Up
Ask a New Question
Mathematics
Algebra
Geometric Progression
Three consecutive terms of a Geometric Progression are ? 6, p and ? 32 . find the value of p.
1 answer
p = √(32/6)
You can
ask a new question
or
answer this question
.
Related Questions
The sum of the 3 terms in arithmetic sequence is 39.if these numbers is increased by 1,5 and 12 respectively the numbers would
The 5th and 10th terms of an arithmetic progression are 18 and -2 respectively.
(a) Find the common difference and the first
The first, second and third terms of a geometric progression are 2k+3, k+6 and k, respectively. Given that all the terms of
A Geometric progression X has a first term of 4a and its sixth term is 256. Another Geometric progression Y has a first term of
find the 7th term of the geometric progression if the first and 5th terms are 16 and 9 respectively.
The third, fifth and seventeenth terms of an arithmetic progression are in geometric progression. Find the common ratio of the
find x if x-3, 3x+5 and 18x-5 are three consecutive term of a geometric progression
If 6, p and 14 are consecutive terms in arithmetic progression(A.P) Find the value of p
find X if the numbers X+3, 5x-3, and 7x+3 are three consecutive terms of a G.P of positive terms. with this value X and given
The numbers p,10 and q are 3 consecutive terms of an arithmetic progression .the numbers p,6 and q are 3 consecutive terms of a
