In a chemical atomic weight determination, the tin content of 3.7692 g of SnCl4 was found to be 1.7170 g. If the atomic weight of Chlorine is taken as 35.253, what is the determined value for the atomic weight of tin from this experiment?
I already know the answer, 118.64. It was given. What I'm stuck on is the process. Can somebody explain how to set this up? Thanks.
To determine the atomic weight of tin (Sn), we can use the given information about the tin content in SnCl4 and the atomic weight of chlorine (Cl).
Step 1: Find the mass of tin in SnCl4:
Mass of tin = Mass of SnCl4 - Mass of chlorine
Mass of tin = 3.7692 g - 1.7170 g
Mass of tin = 2.0522 g
Step 2: Find the number of moles of tin:
Number of moles = Mass / Atomic weight
Number of moles of tin = 2.0522 g / (atomic weight of tin)
Step 3: Find the atomic weight of tin:
Atomic weight of tin = Mass / Number of moles
Atomic weight of tin = 2.0522 g / (number of moles of tin)
Given that the atomic weight of chlorine is 35.253, we can find the number of moles of tin using the molecular formula of SnCl4:
SnCl4 contains 1 tin atom and 4 chlorine atoms.
From the given information, the mass of chlorine is 1.7170 g, with an atomic weight of 35.253 g/mol.
Step 4: Find the number of moles of chlorine:
Number of moles of chlorine = Mass of chlorine / Atomic weight of chlorine
Number of moles of chlorine = 1.7170 g / 35.253 g/mol
Step 5: Determine the number of moles of tin:
SnCl4 contains 1 tin atom and 4 chlorine atoms.
So, moles of tin = moles of chlorine / 4
Step 6: Calculate the atomic weight of tin:
Atomic weight of tin = Mass of tin / Number of moles of tin
Atomic weight of tin = 2.0522 g / (moles of tin)
Following these steps, we can determine the experimental atomic weight of tin.
To determine the atomic weight of tin (Sn) based on the given information, we can use the concept of stoichiometry and molar ratios.
Let's break down the steps:
Step 1: Determine the moles of tin in SnCl4.
To calculate the moles of tin, we divide the mass of tin by its molar mass. Given the mass of tin (SnCl4) as 1.7170 g, we first need to determine its molar mass.
The molar mass of SnCl4 is the sum of the molar masses of the individual elements:
Molar mass of SnCl4 = (molar mass of Sn) + 4 * (molar mass of Cl)
The molar mass of tin (Sn) is not provided, so we need to find it. We can use the molar mass of chlorine (Cl) given as 35.253 g/mol to find the molar mass of tin.
Step 2: Calculate the moles of tin using the determined molar mass.
Now that we have the molar mass of SnCl4, we can calculate the moles of tin using the given mass of tin (1.7170 g) and the molar mass of tin (Sn).
Step 3: Determine the atomic weight of tin.
The atomic weight of an element is the weighted average of the masses of its isotopes, considering their natural abundance. In this case, we assume that all the tin in SnCl4 is the same isotope with an atomic weight given as X.
Using the moles of tin obtained in Step 2 and knowing that the tin content of SnCl4 is 3.7692 g, we can set up the following equation:
(moles of tin) * (atomic weight of tin) = 3.7692 g
Step 4: Solve for the atomic weight of tin.
Using the information provided and the equation from Step 3, you can substitute the values and solve for the atomic weight of tin (X).
After performing the calculations, the determined atomic weight of tin from this experiment should be approximately 118.64 g/mol.
0.0145533713 is the number of moles of Sn present, found from the fact that the number of moles of Sn is 1/4 the number of moles of Cl (massCl/molmassCl)
MolmassSn=massSn/numbermolesSn
117.98 according to the numbers. Check my thinking.