f the pressure of 2 L of a gas at STP doubles, the new volume would be
If temperature is constant, Boyles laws rules:
PV=constant
If p doubles, v is 1/2
According to the principle of Boyle's law, which states that pressure and volume are inversely proportional at constant temperature, we can determine the new volume using the equation:
P1 * V1 = P2 * V2
Where P1 and V1 represent the initial pressure and volume, and P2 and V2 represent the final pressure and volume.
At STP (Standard Temperature and Pressure), the pressure is 1 atm, and the volume is 2 L. If the pressure doubles, the new pressure is 2 * 1 atm = 2 atm.
Let's substitute these values into the equation and solve for V2:
(1 atm) * (2 L) = (2 atm) * V2
2 L = 2 atm * V2
Dividing both sides of the equation by 2 atm:
V2 = 2 L / 2 atm
V2 = 1 L
Therefore, if the pressure of 2 L of gas at STP doubles, the new volume would be 1 L.
To determine the new volume, we need to understand the relationship between pressure and volume of a gas. According to Boyle's Law, the pressure and volume of a gas are inversely proportional, assuming the temperature and amount of gas remain constant. This means that as pressure increases, volume decreases, and vice versa.
At STP (Standard Temperature and Pressure), the pressure is defined as 1 atmosphere (atm) and the temperature is 0 degrees Celsius (273.15 Kelvin). Therefore, if the pressure of 2 L of a gas at STP doubles, we can use Boyle's Law to find the new volume.
Boyle's Law can be expressed as:
P₁V₁ = P₂V₂
Where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume.
In this case, the initial pressure (P₁) is 1 atm, the initial volume (V₁) is 2 L, and the final pressure (P₂) is 2 atm (doubled). We can plug these values into the formula and solve for the new volume (V₂):
(1 atm)(2 L) = (2 atm)(V₂)
2 L atm = 2 atm V₂
2 L = V₂
Therefore, the new volume would be 2 L if the pressure of 2 L of a gas at STP doubles.