Let’s say you have a bedroom drawer that contains about 2 red socks, 4 white socks, and 8 blue socks. Without looking in the drawer, you pick out a sock, take it back, and then pick out a second sock. What could the probability be if the first sock is white and the second sock is blue? Write the final answer is a/b.

Question

Let’s say you have a bedroom drawer that contains about 2 red socks, 4 white socks, and 8 blue socks. Without looking in the drawer, you pick out a sock, take it back, and then pick out a second sock. What could the probability be if the first sock is white and the second sock is blue? Write the final answer is a/b.

P(first sock is white and second sock is blue)=

(My answer is 6/49) is that right?

Answer 1

No

Prob(first is white) = 4/14 = 2/7
now there are only 13 socks left, so
prob(2nd is blue) = 8/13

prob(1st white, then blue) = (2/7)(8/13) = 16/91

Answer 2

To calculate the probability of picking a white sock first and then a blue sock second, we need to consider the total number of possible outcomes and the favorable outcomes.

First, we calculate the total number of outcomes by multiplying the number of choices for the first sock by the number of choices for the second sock. In this case, we have 4 choices for the first white sock and 8 choices for the second blue sock, resulting in a total of 4 * 8 = 32 possible outcomes.

Next, we calculate the number of favorable outcomes, which is the number of ways we can pick a white sock first and a blue sock second. We have 4 white socks to choose from initially and 8 blue socks to choose from second, so we have 4 * 8 = 32 favorable outcomes.

Finally, we calculate the probability by dividing the number of favorable outcomes by the total number of outcomes. Therefore, the probability is 32/32 = 1.

So, the correct answer would be 1, not 6/49.