Please help me solve this equation? Sorry my addition and equal key does not work.
-x^2-3x plus 5 equal 0
Stop switching names and stick to one name only
-x^2 - 3x + 5 = 0
x^2 + 3x - 5 = 0
use the quadratic formula
x = (-3 ± √29)/2
Thank you for explaining to me on how to get the answer.I changed my name because it seems like I was getting overlooked when I really needed the help.
Sure, I can help you with that. To solve the equation -x^2 - 3x + 5 = 0, we can use the quadratic formula.
The quadratic formula is:
x = (-b ± √(b^2 - 4ac)) / (2a)
In the given equation, the coefficients are:
a = -1
b = -3
c = 5
Plugging these values into the quadratic formula, we can calculate the solutions for x.
x = (-(-3) ± √((-3)^2 - 4(-1)(5))) / (2*(-1))
x = (3 ± √(9 + 20)) / (-2)
x = (3 ± √29) / (-2)
So the solutions to the equation are:
x = (3 + √29) / -2
x = (3 - √29) / -2
Please note that the ± symbol represents two possible solutions, one with a plus sign and the other with a minus sign.
If you have a calculator, you can directly plug in the values in the formula to find the solutions.