Renee is twice as old as Dana. Four years ago Renee was three times as old as Dana. How old are Renee and Dana now?
Show Work
Now:
Dana ---- x
Renee --- 2x
4 years ago:
Dana = x-4
Renee = 2x-4
"Four years ago Renee was three times as old as Dana" ---> 2x-4 = 2(x-4)
solve for x, very straight-forward
Let's assume Renee's current age is "R" and Dana's current age is "D".
We are given two pieces of information:
1. Renee is twice as old as Dana: R = 2D
2. Four years ago, Renee was three times as old as Dana: (R - 4) = 3(D - 4)
To solve this system of equations, we can substitute the value of R from the first equation into the second equation:
(2D - 4) = 3(D - 4)
Simplifying the equation:
2D - 4 = 3D - 12
-D = -8
D = 8
Now, we can substitute the value of D back into the first equation to find R:
R = 2D
R = 2(8)
R = 16
Therefore, Renee is currently 16 years old and Dana is currently 8 years old.