The reusably booster rockets of the U.S space shuttle employ a mixture of aluminum and ammonium perchlorate for fuel. A possile equation for this reaction is
3Al+3NH4CLO4---> Al2O3+ AlCl+ 3NO+ 6H2O
What mass of the NH4CLO4 should be used in the fuel mixture for every kilogram of Al?
Can someone explain this problem step by step to? Im really lost.
look at the mole ratios. 3 moles of ammoniumperchlorate for 3moles of aluminum.
How much does each mole weigh? That gives you the mass ratio.
imfao no sorry
To solve this problem, we need to determine the molar ratio between aluminum (Al) and ammonium perchlorate (NH4CLO4) in the given reaction. This ratio will tell us how many moles of NH4CLO4 are required for every mole of Al.
Let's start by examining the balanced equation provided:
3Al + 3NH4CLO4 ---> Al2O3 + AlCl + 3NO + 6H2O
From this equation, we can see that for every 3 moles of Al, we need 3 moles of NH4CLO4. Therefore, the molar ratio between Al and NH4CLO4 is 1:1.
Next, we need to calculate the molar masses of Al and NH4CLO4 to determine the mass ratio between the two compounds.
The molar mass of Al is 27 g/mol.
The molar mass of NH4CLO4 is calculated as follows:
Molar mass of N = 14 g/mol
Molar mass of H = 1 g/mol
Molar mass of Cl = 35.5 g/mol
Molar mass of O = 16 g/mol
Molar mass of NH4CLO4 = (14 * 4) + 1 + (35.5 * 4) + (16 * 4) = 117.5 g/mol
So now we know that the molar ratio of Al to NH4CLO4 is 1:1, and the molar masses of Al and NH4CLO4 are 27 g/mol and 117.5 g/mol, respectively.
To find the mass of NH4CLO4 needed per kilogram of Al, we can use the following steps:
Step 1: Convert the mass of Al to moles of Al.
Given: 1 kilogram of Al.
Mass of Al in grams = 1 kg * 1000 g/kg = 1000 g.
Moles of Al = Mass of Al (in grams) / Molar mass of Al.
Step 2: Calculate the moles of NH4CLO4 using the moles of Al.
Since the molar ratio between Al and NH4CLO4 is 1:1, the moles of NH4CLO4 will be equal to the moles of Al.
Step 3: Convert the moles of NH4CLO4 to mass of NH4CLO4.
Mass of NH4CLO4 = Moles of NH4CLO4 * Molar mass of NH4CLO4.
Let's plug in the values we have:
Moles of Al = 1000 g Al / 27 g/mol
Moles of NH4CLO4 = Moles of Al
Mass of NH4CLO4 = Moles of NH4CLO4 * Molar mass of NH4CLO4
By following these steps and calculating the values, you can determine the mass of NH4CLO4 required in the fuel mixture for every kilogram of Al in the given reaction.