math

mike can run the mile in 6 minutes and dan can run the mile in 9 minutes. If mike gives dan a head start of 1 minute, how far from the start will mike pass dan?

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asked by jackie
  1. mike speed = (1/6) mile/min
    dan speed = (1/9) mile/min
    t-1 = mike time
    t = dan time
    distance = rate * time = same for both
    d = (1/6) (t-1) = (1/9)(t)
    3 t -3 = 2 t
    t = 3 minute
    distance = 3/9 = 1/3 mile

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    posted by Damon
  2. ratemike=1/6 ratedan=1/9

    distancemike=ratemike*time
    distancedan=ratedan(time-1)
    set these equal, and solve for time.
    Then, use the first equation to find out how far mike traveled. time will be in minutes, distance in miles.

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