Suppose the days of the year are numbered from 1 to 365 and January 1 falls on a Tuesday as it did in 2008. What is the correct For statement to use if you want only the numbers for the Thursdays in 2008?
3,10,17, 24, ... 3+n*7....3+51*7
To find the numbers for the Thursdays in 2008, you can use a `for` loop along with the `datetime` module in Python. Here's the correct `for` statement:
```python
import datetime
for day in range(1, 366):
date = datetime.date(2008, 1, 1) + datetime.timedelta(day - 1)
if date.weekday() == 3: # Thursday is represented by number 3
print(date.day)
```
Explanation:
1. The `datetime` module is imported to work with dates and time.
2. The `for` loop iterates through the numbers from 1 to 365 (inclusive) using the `range` function.
3. In each iteration, a `date` object is created by adding the current day (or day - 1) to January 1, 2008 using `datetime.timedelta`.
4. The `weekday()` method is used to check the day of the week, where Monday is represented by 0 and Sunday by 6.
5. If the `weekday()` method returns 3, it means it is a Thursday.
6. Finally, the `day` attribute of the `date` object is printed, which represents the day of the month.