A car can brake to a stop from 60mph in 2.6 seconds. If the car has a weight of 3225 lbs, what force in Newton's acts on the car.
F=ma, vt=v0+at, a=(vt-v0)/t=(0-60mph)/2.6s=-23.1m/s^2
3225 lbs=1462.84 kg
thus F=1462.84kg*(-23.1m/s^2)=-63.3N
Vo = 60mi/h * 1600m/mi * 1h/3600s = 26.67 m/s
V = Vo + a*t = 0
a = -Vo/t = -26.67/2.6 = -10.26 m/s^2
M = 3225Lbs * 0.454kg/1Lb = = 1464 kg
F = M*a = 1464 * (-10.26) = -15,022 N.
Note: Your answer would have been correct if you had converted 60 mph to
m/s.
To calculate the force acting on the car, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a): F = ma.
First, let's convert the weight of the car from pounds to kilograms. We know that 1 pound is equal to 0.453592 kilograms. Therefore, 3225 lbs can be converted to kilograms by multiplying this weight by the conversion factor: 3225 lbs * 0.453592 kg/lb = 1462.84 kg.
Next, we need to find the acceleration of the car. We are given that the car can brake to a stop from a speed of 60 mph in 2.6 seconds. To find the acceleration, we can use the formula v = v0 + at, where v is the final velocity, v0 is the initial velocity, a is the acceleration, and t is the time.
Since the car comes to a stop, the final velocity is 0 m/s, and the initial velocity is 60 mph. To convert 60 mph to meters per second, we can multiply this speed by the conversion factor 0.44704 m/s per mph: 60 mph * 0.44704 m/s per mph = 26.8224 m/s.
Now we can plug in the values into the equation to find the acceleration. Rearranging the equation, we have: a = (v - v0) / t. Substituting the values, we get: a = (0 m/s - 26.8224 m/s) / 2.6 s = -23.1 m/s^2.
Finally, we can calculate the force acting on the car by multiplying the mass and acceleration: F = 1462.84 kg * -23.1 m/s^2 = -63.3 N.
Therefore, the force acting on the car while braking to a stop is approximately -63.3 Newtons.