From what height was a brick dropped if it hit the ground with a speed of 4.3 m/s?
vf=gt
4.3=9.8*t
solve for time t.
But how can you go through step by step with me?
Velocity = gravity x time
velocity = 4.3 m/s
gravity (constant) = 9.8 m/s/s
4.3 = 9.8 x time
4.3 / 9.8 = 9.8 x time / 9.8
4.3 / 9.8 = time
.439 = time
To determine the height from which a brick was dropped, we can use the principles of physics, specifically the equations of motion.
We'll need to use the equation for free fall motion, which is given by:
v^2 = u^2 + 2as
where:
v = final velocity (in this case, the speed of the brick when it hits the ground, 4.3 m/s)
u = initial velocity (which is 0 m/s since the brick is dropped, not thrown)
a = acceleration due to gravity (approximately 9.8 m/s^2)
s = distance or height traveled by the brick
Rearranging the equation, we have:
s = (v^2 - u^2) / (2a)
Substituting the given values:
s = (4.3^2 - 0^2) / (2 * 9.8) = 0.934 m
Therefore, the brick was dropped from a height of approximately 0.934 meters.