What is the midpoint of the line segment whose endpoints are (-8, 12) and (-13, -2)?
A(-8, 12), M(x, y), B(-13, -2)
X = ((-8) + (-13))/2 = -10 1/2 = -21/2
Y = (12 + (-2))/2 = 5
M(-21/2, 5)
To find the midpoint of a line segment with given endpoints, you can use the midpoint formula. The midpoint formula states that the coordinates (x, y) of the midpoint of a line segment with endpoints (x₁, y₁) and (x₂, y₂) are:
x = (x₁ + x₂) / 2
y = (y₁ + y₂) / 2
In this case, the endpoints are (-8, 12) and (-13, -2).
Using the midpoint formula:
x = (-8 + (-13)) / 2
y = (12 + (-2)) / 2
Simplifying:
x = (-8 - 13) / 2
y = (12 - 2) / 2
x = -21 / 2
y = 10 / 2
x = -10.5
y = 5
So, the midpoint of the line segment is (-10.5, 5).