. If i = ¡Ì-1, then (i + 1)(6i ¨C 10) is equivalent to?
The fonts mangled your symbols, but if I manage to get it right, we have
i = √-1
(i+1)(6i-10)
= 6i^2 + 6i - 10i - 10
= -6+6i-10i-10
= -16-4i
8.8x10^3 hours in a year approximate how many in one year
To simplify the expression (i + 1)(6i - 10) when i = -√-1, we can follow the given steps:
Step 1: Replace i with -√-1 in the expression.
(i + 1)(6i - 10)
Step 2: Evaluate the values in parentheses.
(-√-1 + 1)(6(-√-1) - 10)
Step 3: Simplify the expression in parentheses.
(0)(-6√-1 - 10)
Step 4: Simplify further.
0
Therefore, (i + 1)(6i - 10) is equivalent to 0 when i = -√-1.