What the minimum of y=2x^2-7x-2? How do you find it?
Finding Equivalent Fraction
Y = 2x^2 - 7x - 2
h = Xv = -B/2A = 7/4.
k = 2*(7/4)^2 - 7*7/4 - 2 = -8.125 =
-8 1/8 = -65/8
P(h, k) = (7/4, -65/8).
To find the minimum of a quadratic function, you can use the vertex formula. The vertex formula is given by the equation x = -b/(2*a), where "a" and "b" are the coefficients of the quadratic equation in the form y = ax^2 + bx + c.
In this case, for the given function y = 2x^2 - 7x - 2, the coefficient of x^2 is 2 (a = 2) and the coefficient of x is -7 (b = -7). To find the x-coordinate of the vertex, we can use the formula x = -(-7)/(2*2) = 7/4.
To find the corresponding y-coordinate of the vertex, we substitute this x-value back into the equation:
y = 2(7/4)^2 - 7(7/4) - 2
Solving this equation will give us the minimum value of y.