2H2S(g)+3O2(g)<-->2SO2(g)+2H2O
SO2(g)+Cl2(g)<-->SO2Cl2(g)
I balanced so how do I find the overall equation
Multiply equation 2 by 2 and add equation 1 to equation 2. Then cancel anything (mole wise) that is common to both sides. For example 2SO2 on the right and 2SO2 on the left will cancel.
To find the overall equation for a series of reactions, you need to eliminate any common compounds or elements that appear on both sides of the equations. In this case, the compound you want to eliminate is SO2, which appears on both sides of the second equation.
First, you need to multiply the first equation by 2 to balance the number of SO2 molecules:
2(2H2S(g) + 3O2(g) → 2SO2(g) + 2H2O)
Now, the number of SO2 molecules is balanced, and we can proceed to eliminate SO2. The balanced equations can be combined as follows:
4H2S(g) + 6O2(g) → 4SO2(g) + 4H2O
SO2(g) + Cl2(g) → SO2Cl2(g)
To eliminate SO2, we need to make the coefficient of SO2 in the first equation equal to 1 (since the coefficient in the second equation is already 1). Dividing the first equation by 4 achieves this:
H2S(g) + (3/2)O2(g) → SO2(g) + H2O
Now, we can combine the two equations to obtain the overall equation:
H2S(g) + (3/2)O2(g) + Cl2(g) → SO2Cl2(g) + H2O
Therefore, the overall equation is:
2H2S(g) + 3O2(g) + 2Cl2(g) → 2SO2Cl2(g) + 2H2O